Selasa, 11 November 2025

IP Address 192.168.1.0/29 Subnet ke 9

 192.168.1.0/29

11111111.11111111.11111111.11111000

255.255.255.248


1. Jumlah subnet = 2^x

                            = 2^5

                            = 32


2. Jumlah host = 2^y

                        = 2^3

                        = 8


3. Blok subnet = 256-248

                       = 8

 ada 32 subnet dimulai dari : 0,8,16,24,32,40,48,56,64,72, 80,88,96,104,112,120,128,136,144,152,160,168,176,184,192,200,208,216,224,232,240,248

karena absen saya 9 maka saya menggunakan angka ke 9 yaitu 64


jadi...

subnet = 192.168.1.64

host pertama = 192.168.1.65

host terakhir = 192.168.1.70

broadcast = 192.168.1.71

IP Address 192.168.1.0/29 Subnet ke 9

 192.168.1.0/29 11111111.11111111.11111111.11111000 255.255.255.248 1. Jumlah subnet = 2^x                             = 2^5               ...